What is the load from a 4-kilowatt electric heater operating at 240 volts?

Get ready for the Fundamentals of Code Calculations Test. Engage with multiple choice questions, complete with insights and explanations. Be prepared to excel!

Multiple Choice

What is the load from a 4-kilowatt electric heater operating at 240 volts?

Explanation:
To determine the load in amps drawn by a 4-kilowatt electric heater operating at 240 volts, we utilize the formula that relates power (P), voltage (V), and current (I): \[ P = V \times I \] Where: - \( P \) is the power in watts (W). - \( V \) is the voltage in volts (V). - \( I \) is the current in amperes (A). First, we convert kilowatts to watts: \[ 4 \text{ kW} = 4,000 \text{ W} \] Next, we rearrange the formula to solve for current (I): \[ I = \frac{P}{V} \] Substituting the known values: \[ I = \frac{4000 \text{ W}}{240 \text{ V}} \] Calculating this gives: \[ I = \frac{4000}{240} \approx 16.67 \text{ A} \] Thus, the correct current draw from a 4-kilowatt heater operating at 240 volts is approximately 16.67 A. The result corresponds to the first choice

To determine the load in amps drawn by a 4-kilowatt electric heater operating at 240 volts, we utilize the formula that relates power (P), voltage (V), and current (I):

[

P = V \times I

]

Where:

  • ( P ) is the power in watts (W).

  • ( V ) is the voltage in volts (V).

  • ( I ) is the current in amperes (A).

First, we convert kilowatts to watts:

[

4 \text{ kW} = 4,000 \text{ W}

]

Next, we rearrange the formula to solve for current (I):

[

I = \frac{P}{V}

]

Substituting the known values:

[

I = \frac{4000 \text{ W}}{240 \text{ V}}

]

Calculating this gives:

[

I = \frac{4000}{240} \approx 16.67 \text{ A}

]

Thus, the correct current draw from a 4-kilowatt heater operating at 240 volts is approximately 16.67 A. The result corresponds to the first choice

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy